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  1. #include <stdio.h>
  2.  
  3. int sum[3]; 
  4. void calculate(int (*a)[4]) {
  5.     for (int i=0;i<3;i++) {
  6.         sum[i] = 0;
  7.         for (int j=0;j<4;j++) {
  8.             sum[i] += a[i][j];
  9.         }
  10.         printf("第%d行の合計 (sum[%d]): %d\n", i + 1, i, sum[i]);
  11.     }
  12. }
  13.  
  14. int main(void) {
  15.     int a[3][4] = {{1,2,3,4},{5,6,7,8},{9,10,11,12}};
  16.     calculate(a);
  17.     return 0;
  18. }
Success #stdin #stdout 0.01s 5288KB
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stdin
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Standard input is empty
stdout
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第1行の合計 (sum[0]): 10
第2行の合計 (sum[1]): 26
第3行の合計 (sum[2]): 42
https://ideone.com/zLp5S2
第４回 提出課題1
language:
C99 (gcc 8.3)
created:
4 days ago
visibility:
public

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