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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. #define int              long long int
  4. #define double           long double
  5. #define print(a)         for(auto x : a) cout << x << " "; cout << endl
  6.  
  7.  
  8. const int M = 1000000007;
  9. const int N = 3e5+9;
  10. const int INF = 2e9+1;
  11. const int LINF = 2000000000000000001;
  12.  
  13. inline int power(int a, int b, int mod=M) {
  14.     int x = 1;
  15.     a %= mod;
  16.     while (b) {
  17.         if (b & 1) x = (x * a) % mod; 
  18.         a = (a * a) % mod;
  19.         b >>= 1;
  20.     }
  21.     return x;
  22. }
  23.  
  24.  
  25. //_ ***************************** START Below *******************************
  26.  
  27.  
  28.  
  29.  
  30. string a;
  31.  
  32. int consistency1(int n){
  33.  
  34. 	vector<vector<bool>> dp(n, vector<bool>(n, false));
  35. 	vector<vector<int>> dpCt(n, vector<int>(n, 0));
  36.  
  37. 	for(int gap=0; gap<n; gap++){
  38. 		for(int i=0, j=gap; j<n; i++, j++){
  39. 			if(gap == 0){
  40. 				dp[i][j] = true;
  41. 				dpCt[i][j] = 1;
  42. 			}
  43. 			else if(gap == 1){
  44. 				if(a[i] == a[j]){
  45. 					dp[i][j] = true;
  46. 					dpCt[i][j] = 3;
  47. 				}
  48. 				else{
  49. 					dpCt[i][j] = 2;
  50. 				}
  51. 			}
  52. 			else{
  53. 				dpCt[i][j] = dpCt[i][j-1] + dpCt[i+1][j] - dpCt[i+1][j-1];
  54. 				if(a[i] == a[j] && dp[i+1][j-1]){
  55. 					dp[i][j] = true;
  56. 					dpCt[i][j]++;
  57. 				}
  58. 			}
  59. 		}
  60. 	}
  61.  
  62. 	int ans = 0;
  63. 	for(int i=0; i<=n-2; i++){
  64. 		int j = i;
  65. 		int x = 0;
  66. 		while(j>=0){
  67. 			if(dp[j][i]) x++;
  68. 			j--;
  69. 		}
  70. 		int y = dpCt[i+1][n-1];
  71.  
  72. 		ans += x*y;
  73. 	}
  74.  
  75.     return ans;
  76. }
  77.  
  78.  
  79.  
  80.  
  81.  
  82.  
  83.  
  84. int consistency2(int n){
  85.  
  86. 	vector<vector<bool>> dp(n, vector<bool>(n, false));
  87. 	vector<vector<int>> dpCt(n, vector<int>(n, 0));
  88. 	vector<int> endsAt(n, 0);
  89.  
  90. 	for(int gap=0; gap<n; gap++){
  91. 		for(int i=0, j=gap; j<n; i++, j++){
  92. 			if(gap == 0){
  93. 				dp[i][j] = true;
  94. 				dpCt[i][j] = 1;
  95. 				endsAt[j] += 1;
  96. 			}
  97. 			else if(gap == 1){
  98. 				if(a[i] == a[j]){
  99. 					dp[i][j] = true;
  100. 					dpCt[i][j] = 3;
  101. 					endsAt[j] += 1;
  102. 				}
  103. 				else{
  104. 					dpCt[i][j] = 2;
  105. 				}
  106. 			}
  107. 			else{
  108. 				dpCt[i][j] = dpCt[i][j-1] + dpCt[i+1][j] - dpCt[i+1][j-1];
  109. 				if(a[i] == a[j] && dp[i+1][j-1]){
  110. 					dp[i][j] = true;
  111. 					dpCt[i][j]++;
  112. 					endsAt[j]++;
  113. 				}
  114. 			}
  115. 		}
  116. 	}
  117.  
  118.  
  119. 	// vector<int> endsAt(n, 0);
  120. 	// for(int j = 0; j < n; j++){
  121. 	// 	for(int i = 0; i <= j; i++){
  122. 	// 		if(dp[i][j]) endsAt[j]++;
  123. 	// 	}
  124. 	// }
  125.  
  126. 	int ans = 0;
  127. 	for(int i=0; i<=n-2; i++){
  128. 		int x = endsAt[i];
  129. 		int y = dpCt[i+1][n-1];
  130.  
  131. 		ans += x*y;
  132. 	}
  133.  
  134.     return ans;
  135. }
  136.  
  137.  
  138.  
  139.  
  140.  
  141.  
  142.  
  143.  
  144.  
  145.  
  146.  
  147.  
  148.  
  149.  
  150. int practice(int n){
  151.  
  152.  
  153.     return 0;
  154. }
  155.  
  156.  
  157.  
  158.  
  159.  
  160. void solve() {
  161.  
  162.     cin >> a;
  163.     int n = a.size();
  164.     cout << consistency1(n) << " " << consistency2(n) << endl;
  165.  
  166.  
  167. }
  168.  
  169.  
  170.  
  171.  
  172.  
  173. int32_t main() {
  174.     ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
  175.  
  176.     int t = 1;
  177.     // cin >> t;
  178.     while (t--) {
  179.         solve();
  180.     }
  181.  
  182.     return 0;
  183. }
Success #stdin #stdout 0s 5316KB
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https://ideone.com/XdoVe0
language:
C++14 (gcc 8.3)
created:
1 day ago
visibility:
public

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