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  1. nums = [5,12,7,9,21,7,14]
  2. count_seven = nums.count(7)
  3. print("数字7出现的次数",count_seven)
  4. if 99 not in nums:
  5. 	nums.append(99)
  6. print("添加99后的列表",nums)
  7.  
  8. nums.remove(7)
  9. print("删除第一个7后的列表",nums)
  10. sub_list = nums[1:4]
  11. print("第2~4个元素组成的列表",sub_list)
Success #stdin #stdout 0.07s 14124KB
comments (?)
stdin 
Standard input is empty
stdout 
数字7出现的次数 2
添加99后的列表 [5, 12, 7, 9, 21, 7, 14, 99]
删除第一个7后的列表 [5, 12, 9, 21, 7, 14, 99]
第2~4个元素组成的列表 [12, 9, 21]
https://ideone.com/MzgvyX
language:
Python 3 (python  3.12)
created:
1 day ago
visibility:
public

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