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  1. #include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4.     int i = 0;
  5.     int j = 0;
  6.  
  7.  
  8.     while (s[j] != '\0') {
  9.         j++;
  10.     }
  11.     j--;
  12.  
  13.     while (i < j) {
  14.         if (s[i] != s[j]) {
  15.             return 0;
  16.         }
  17.         i++;
  18.         j--;
  19.     }
  20.  
  21.     return 1;
  22. }
  23.  
  24. // メイン関数はそのままでOK
  25. int main(){
  26.     char s[100];
  27.     scanf("%s",s);
  28.     printf("%s -> %d\n",s,isPalindrome(s));
  29.     return 0;
  30. }
Success #stdin #stdout 0s 5300KB
comments (?)
stdin
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ajbdgbujhjl
stdout
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ajbdgbujhjl -> 0
https://ideone.com/5Hac9q
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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