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  1. class DebugOne4
  2. {
  3.    public static void main(String[] args)
  4.    {
  5.       System.out.print("This output");
  6.       System.out.println(" is on the same line as the last one.");
  7.       System.out.println("But this is on a new one.");
  8.    }
  9. }
Success #stdin #stdout 0.1s 52628KB
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stdin
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Standard input is empty
stdout
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This output is on the same line as the last one.
But this is on a new one.
https://ideone.com/1qLVl1
language:
Java (HotSpot 12)
created:
5 days ago
visibility:
public

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